Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. The number is entered through Scanner class and then its square is taken by multiplying the number 2 times.After that we find the sum of digits of the square and check if the number is equal to the sum of digits of square of the number. This function is useful in a number of numeric algorithms. Receive input from the user for the value to store the variable num and to find the sum of digits. I am Bhupendra Patidar, full-stack Java developer, and Automation engineer. Write a program that accepts a positive number as input and calculates the sum of squares of individual digits of the given number. A positive integer n is said to be good if there exists a perfect square whose sum of digits in base 10 is equal to n. For instance, 13 is good because (7^2)=49 and 4+9=13. e.g., if the input is 6, then the sum is 1 + 2 + 3 + 4 + 5 + 6 = 21; Else replace the number with the sum of the square of digits. Write a program to read a number, calculate the sum of odd digits (values) present in the given number. *; public class Square { public static void main(String args[]) { Scanner sc=new Scanner(System.in); int num; System.out.print("Enter a number which is integer format: "); num=sc.nextInt(); System.out.println("The square of "+ num + " is: "+ Math.pow(num, 2)); } } Output: static int squaresum (int n) {. After the check, the corresponding statements if the number is Neon Number or not is printed. Divide the number by 10. You can learn more tutorials here and Java interview questions for beginners. Math.sqrt(m): It is used to get the square root of any number, it will return square root of m. By making use of the above theorem, we can directly find out if the given number c c c can be expressed as a sum of two squares. Find Whether a Number Can Be the Sum of Two Squares – Brute Force Algorithm. Check Sum of Odd Digits in java Java Interview Programming problem Input: N = 457892 Output: Sum odd = 20 Sum even = 15 Refer sample output for formatting specifications. This Java program allows the user to enter the maximum limit value. Let us discuss those methods in detail. // Return the sum of square of first n natural numbers. Else, replace the number with the sum of … The following Java program computes the sum of digits of a number. class GFG {. // Iterate i from 1 and n. // finding square of i and add to sum. To calculate the sum of values of a Map

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